Questions
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- 1. Refer to the figure given below. The values of \(I_1\), \(I_2\) and \(I_3\) are __________.
2026 Hard - 2. The current flowing through the \(1 \Omega\) resistor is \(\frac{\mathrm{n}}{10} \ A.\) The value of \(n\) is _______.
2024 Hard - 3. Three voltmeters, all having different internal resistances are joined as shown in figure. When some potential difference is applied across \(\mathrm{A}\) and \(B\), their readings are \(V_1, V_2\) and \(V_3\). Choose the correct option.
2024 Hard - 4. Figure shows a part of an electric circuit. The potentials at points \(a , b\) and \(c\) are \(30\,V , 12\,V\) and \(2\,V\) respectively. The current through the \(20 \Omega\) resistor will be \(........\,A\)
2023 Hard - 5. For the network shown below, the value \(V _{ B }- V _{ A }\) is_______ \(V\)
2022 Medium - 6. A \(16\, \Omega\) wire is bend to form a square loop. A \(9 \,{V}\) supply having internal resistance of \(1 \,\Omega\) is connected across one of its sides. The potential drop across the diagonals of the square loop is \(.......\,\times 10^{-1} \,{V}\) 2021 Medium
- 7. A cell \(E _{1}\) of \(emf 6 V\) and internal resistance \(2 \Omega\) is connected with another cell \(E _{2}\) of \(emf 4 V\) and internal resistance \(8 \Omega\) (as shown in the figure). The potential difference across points \(X\) and \(Y\) is............ \(V\)
2021 Hard - 8. The value of current in the \(6 \,\Omega\) resistance is \(....\,A\)
2021 Hard - 9. Four resistances \(40 \ \Omega, 60\ \Omega, 90\ \Omega\) and \(110\ \Omega\) make the arms of a quadrilateral \(A,B,C,D\). Across \(AC\) is a battery of emf \(40\, V\) and internal resistance negligible. The potential difference across \(BD\) is \(V\) is......
2020 Medium - 10. In the circuit, given in the figure currents in different branches and value of one resistor are shown. Then potential at point \(B\) with respect to the point \(A\) is\(.......V\)
2020 Hard - 11. In the figure shown, the current in the \(10\, V\) battery is close to
2020 Medium - 12. The galvanometer deflection, when key \(K_1\) is closed but \(K_2\) is open, equals \(\theta_0\) (see figure). On closing \(K_2\) also and adjusting \(R_2\) to \(5\,\Omega \) , the deflection in galvanometer becomes \(\frac{{\theta _0}}{5}\). The resistance of the galvanometer is, then, given by [Neglect the internal resistance of battery]: .................. \(\Omega\)
2019 Hard - 13. When the switch \(S\), in the circuit shown, is closed, then the value of current \(i\) will be ................. \(A\)
2019 Medium - 14. Two batteries with e.m.f \(12\ V\) and \(13\ V\) are connected in parallel across a load resistor of \(10\,\Omega\) . The internal resistances of the two batteries are \(1\,\Omega\) and \(2\,\Omega\) respectively. The voltage across the load lies between 2018 Medium
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Other STD 12 - Current electricity topics
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Frequently asked
How many Kirchhoff's Law questions came in JEE Mains?
14 questions from 2018–2026, each with the correct answer and a full solution.
How difficult are Kirchhoff's Law questions?
0% are easy, 43% medium and 57% hard.