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JEE Mains · Physics · STD 12 - Current electricity
  • JEE Mains 2021
  • Hard
  • Numerical

The value of current in the \(6 \,\Omega\) resistance is \(....\,A\)

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Answer & Solution

Correct Answer

(D) \(10\)

Step-by-step Solution

Detailed explanation

Applying \(KCL\) at point \(P,\)

\(\frac{V-0}{6}+\frac{V-90}{5}+\frac{V-140}{20}=0\)

\(\Rightarrow 10 {V}+12 {V}-1080+3 {V}-420=0\)

\(\Rightarrow {V}=60\)

\(\therefore \text { Current in } 6 \Omega=\frac{{V}-0}{6}=10 {A}\)

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