JEE Mains · Physics · STD 12 - Current electricity
- JEE Mains 2021
- Hard
- Numerical
The value of current in the \(6 \,\Omega\) resistance is \(....\,A\)

Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(10\)
Step-by-step Solution
Detailed explanation
Applying \(KCL\) at point \(P,\)
\(\frac{V-0}{6}+\frac{V-90}{5}+\frac{V-140}{20}=0\)
\(\Rightarrow 10 {V}+12 {V}-1080+3 {V}-420=0\)
\(\Rightarrow {V}=60\)
\(\therefore \text { Current in } 6 \Omega=\frac{{V}-0}{6}=10 {A}\)
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