JEE Mains · Physics · STD 12 - 3. current electricity
The value of current in the \(6 \,\Omega\) resistance is \(....\,A\)
- A \(4\)
- B \(6\)
- C \(8\)
- D \(10\)
Answer & Solution
Correct Answer
(D) \(10\)
Step-by-step Solution
Detailed explanation
Applying \(KCL\) at point \(P,\) \(\frac{V-0}{6}+\frac{V-90}{5}+\frac{V-140}{20}=0\) \(\Rightarrow 10 {V}+12 {V}-1080+3 {V}-420=0\) \(\Rightarrow {V}=60\) \(\therefore \text { Current in } 6 \Omega=\frac{{V}-0}{6}=10 {A}\)
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