JEE Mains · Physics · STD 12 - 3. current electricity
Three voltmeters, all having different internal resistances are joined as shown in figure. When some potential difference is applied across \(\mathrm{A}\) and \(B\), their readings are \(V_1, V_2\) and \(V_3\). Choose the correct option.
- A \(V_1=V_2\)
- B \(V_1 \neq V_3-V_2\)
- C \(V_1+V_2>V_3\)
- D \(V_1+V_2=V_3\)
Answer & Solution
Correct Answer
(D) \(V_1+V_2=V_3\)
Step-by-step Solution
Detailed explanation
From \(KVL\), \(v_1+v_2-v_3=0 \Rightarrow \mathrm{V}_1+\mathrm{V}_2=\mathrm{V}_3\)
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