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JEE Mains · Physics · STD 12 - Current electricity
  • JEE Mains 2020
  • Medium
  • MCQ

In the figure shown, the current in the \(10\, V\) battery is close to

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Answer & Solution

Correct Answer

(C) \(0.21\, A\) from positive to negative terminal.

Step-by-step Solution

Detailed explanation

\(E _{ eq }=\frac{20 \times 10}{17}=\frac{200}{17}\)

and \(R _{ eq }=\frac{7 \times 10}{17}=\frac{70}{17}\)

\(\therefore \quad I=\frac{\frac{20}{17}-10}{4+\frac{70}{17}}=0.21 A\)

from \(+ve\) to \(-ve\) terminal

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