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JEE Mains · Physics · STD 12 - 3. current electricity

A \(16\, \Omega\) wire is bend to form a square loop. A \(9 \,{V}\) supply having internal resistance of \(1 \,\Omega\) is connected across one of its sides. The potential drop across the diagonals of the square loop is \(.......\,\times 10^{-1} \,{V}\)

  1. A \(45\)
  2. B \(40\)
  3. C \(12\)
  4. D \(33\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(45\)

Step-by-step Solution

Detailed explanation

By KVL in outer loop \(9-12 i-4 i=0\) \(16 i=9\) \(8 i =\frac{9}{2}=4.5\) \(=45 \times 10^{-1}\)
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