JEE Mains · Physics · STD 12 - Current electricity
- JEE Mains 2021
- Medium
- Numerical
A \(16\, \Omega\) wire is bend to form a square loop. A \(9 \,{V}\) supply having internal resistance of \(1 \,\Omega\) is connected across one of its sides. The potential drop across the diagonals of the square loop is \(.......\,\times 10^{-1} \,{V}\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(45\)
Step-by-step Solution
Detailed explanation
By KVL in outer loop
\(9-12 i-4 i=0\)
\(16 i=9\)
\(8 i =\frac{9}{2}=4.5\)
\(=45 \times 10^{-1}\)
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