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JEE Mains · Physics · STD 12 - Current electricity
  • JEE Mains 2021
  • Medium
  • Numerical

A \(16\, \Omega\) wire is bend to form a square loop. A \(9 \,{V}\) supply having internal resistance of \(1 \,\Omega\) is connected across one of its sides. The potential drop across the diagonals of the square loop is \(.......\,\times 10^{-1} \,{V}\)

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Verified Solution

Answer & Solution

Correct Answer

(A) \(45\)

Step-by-step Solution

Detailed explanation

By KVL in outer loop

\(9-12 i-4 i=0\)

\(16 i=9\)

\(8 i =\frac{9}{2}=4.5\)

\(=45 \times 10^{-1}\)