\(‘a'\) ત્રિજ્યા અને \('m’\) દળ ધરાવતો ગોળો, અચળ ગતિ \(v_{0}\) સાથે સમક્ષિતીજ સમતલને સમાંતર ગબડે છે. આ દરમ્યાન તે સમક્ષિતીજ સાથે \(\theta\) કોણે નમેલા સમતલ સામનો કરતાં તેના ઉપર ચઢે છે. જો આપણે ધારી લઈએ કે તે લપસ્યા વગર ગબડે છે તો આ ગોળો ઉપરની દિશામાં કેટલું અંતર કાપશે?

A \(\frac{10 v_{0}^{2}}{7 g \sin \theta}\)
B \(\frac{v_{0}^{2}}{5 g \sin \theta}\)
C \(\frac{2}{5} \frac{v_{0}^{2}}{ g \sin \theta}\)
D \(\frac{v_{0}^{2}}{2 g \sin \theta}\)

Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{10 v_{0}^{2}}{7 g \sin \theta}\)

Step-by-step Solution

Detailed explanation

Angular momentum conservation about A \(mv _{0} a \cos \theta+\frac{2}{5} ma ^{2} \omega\) \(= mva +\frac{2}{5} ma ^{2} \omega^{1}\) \(mv _{0} a \left[\frac{2}{5}+\cos \theta\right]=\frac{7}{5} mva\) \(v =\frac{5}{7}= v _{0}\left[\frac{2}{5}+\cos \theta\right]\)…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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