JEE Mains · Physics · STD 12 - 10. Wave optics
In a Young's double slit experiment, the intensities at two points, for the path difference \(\frac{\lambda}{4}\) and \(\frac{\lambda}{3}\) ( \(\lambda\) being the wavelength of light used) are \(I_1\) and \(I_2\) respectively. If \(I_0\) denotes the intensity produced by each one of the individual slits, then \(\frac{ I _1+ I _2}{ I _0}=..............\)
- A \(2\)
- B \(1\)
- C \(3\)
- D \(4\)
Answer & Solution
Correct Answer
(C) \(3\)
Step-by-step Solution
Detailed explanation
\(I =4 I _0 \cos ^2\left(\frac{\Delta \phi}{2}\right)\) \(I _1=4 I _0 \cos ^2\left(\frac{\pi}{4}\right)=2 I _0\) \(I _2=4 I _0 \cos ^2\left(\frac{2 \pi}{3}\right)= I _0\) \(\Rightarrow \frac{ I _1+ I _2}{ I _0}=3\)
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