JEE Mains · Physics · STD 12 - Wave optics
- JEE Mains 2023
- Medium
- MCQ
Given below are two statements : Statement \(I:\) If the Brewster's angle for the light propagating from air to glass is \(\theta_{ B }\), then Brewster's angle for the light propagating from glass to air is \(\frac{\pi}{2}-\theta_B\). Statement \(II:\) The Brewster's angle for the light propagating from glass to air is \(\tan ^{-1}\left(\mu_{ g }\right)\) where \(\mu_{ g }\) is the refractive index of glass. In the light of the above statements, choose the correct answer from the options given below :
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) Statement \(I\) is true but Statement \(II\) is false.
Step-by-step Solution
Detailed explanation
\(\mu_{ a } \sin i_1=\mu_{ g } \sin \left(90- i _1\right)\)
\(\tan i _1=\frac{\mu_{ g }}{\mu_{ a }}\)
When going from glass to air
\(\tan i_2=\frac{\mu_{ a }}{\mu_{ g }}=\cot i_1\)
Hence
\(i_2=\frac{\pi}{2}-i_1\)
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