JEE Mains · Physics · STD 12 - 10. Wave optics
In a Young's double slit experiment, two slits are illuminated with a light of wavelength \(800 nm\). The line joining \(A _1 P\) is perpendicular to \(A _1 A _2\) as shown in the figure. If the first minimum is detected at \(P\), the value of slits separation ' \(a\) ' will be \(.........\,mm\) The distance of screen from slits \(D =5\,cm\)
- A \(0.4\)
- B \(0.5\)
- C \(0.2\)
- D \(0.1\)
Answer & Solution
Correct Answer
(C) \(0.2\)
Step-by-step Solution
Detailed explanation
\(A _2 P - A _1 P =\frac{\lambda}{2} \quad \text { (Condition of minima) }\) \(\sqrt{ D ^2+ a ^2}- D =\frac{\lambda}{2}\) \(D \left(1+\frac{ a ^2}{ D ^2}\right)^{1 / 2}- D =\frac{\lambda}{2}\) \(D \left(1+\frac{1}{2} \times \frac{ a ^2}{ D ^2}\right)- D =\frac{\lambda}{2}\)…
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