JEE Mains · Physics · STD 12 - Current electricity
- JEE Mains 2019
- Medium
- Numerical
In the given circuit the internal resistance of the \(18\,V\) cell is negligible. If \(R_1 = 400 \,\Omega ,\,R_3 = 100\,\Omega \) and \(R_4 = 500\,\Omega \) and the reading of an ideal voltmeter across \(R_4\) is \(5\,V,\) then the value of \(R_2\) will be ........... \(\Omega\)

Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(300\)
Step-by-step Solution
Detailed explanation
\(\frac{12}{400}=\frac{6}{600}+\frac{6}{R_{2}}\)
\(\Rightarrow \quad \frac{1}{200}=\frac{1}{600}+\frac{1}{R_{2}}\)
\(\Rightarrow \quad \mathrm{R}_{2}=300\, \Omega\)
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