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JEE Mains · Physics · STD 12 - Current electricity
  • JEE Mains 2023
  • Medium
  • MCQ

In the network shown below, the charge accumulated in the capacitor in steady state will be ........... \(\mu C\)

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(A) \(7.2\)

Step-by-step Solution

Detailed explanation

No current will flow in capacitor in steady state, current flowing in the circuit in steady state

\(I=\frac{3}{6+4}=\frac{3}{10}\)

Potential difference on \(6\,\Omega\) resistance

\(V=6 \times \frac{3}{10}=1.8 \text { volt }\)

Capacitor will have same potential so charge,

\(q = CV =(4\,\mu F ) \cdot(1.8 \text { volt })=7.2\,\mu C\)

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