JEE Mains · Physics · STD 11- 8. mechanical properties of solids
The density and breaking stress of a wire are \(6 \times\) \(10^4 \mathrm{~kg} / \mathrm{m}^3\) and \(1.2 \times 10^8 \mathrm{~N} / \mathrm{m}^2\) respectively. The wire is suspended from a rigid support on a planet where acceleration due to gravity is \(\frac{1^{\text {rd }}}{3}\) of the value on the surface of earth. The maximum length of the wire with breaking is _______ \(\mathrm{m}\) (take, \(\mathrm{g}=\) \(\left.10 \mathrm{~m} / \mathrm{s}^2\right)\)
- A \(600\)
- B \(700\)
- C \(800\)
- D \(900\)
Answer & Solution
Correct Answer
(A) \(600\)
Step-by-step Solution
Detailed explanation
\(\mathrm{T}=\mathrm{mg}\) \(\sigma=\frac{\mathrm{T}}{\mathrm{A}}=\frac{\mathrm{mg}}{\mathrm{A}}\) \(\frac{(\sigma \mathrm{A} \ell) \mathrm{g}}{\mathrm{A}}\) \(\Rightarrow \ell=\frac{\sigma}{\rho \mathrm{g}}=\frac{1.2 \times 10^8 \times 3}{6 \times 10^4 \times 10}=600\)
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