JEE Mains · Physics · STD 12 -7. Alternating current
A circuit connected to an \(ac\) source of \(emf\) \(e = e_0\, sin\, (1000t)\) with \(t\) in seconds, gives a phase difference of \(\frac{\pi }{4}\) between the \(emf\) \(e\) and current \(i\). Which of the following circuits will exhibit this?
- A \(RC\) circuit with \(R = 1\, k\,\Omega \) and \(C = 1\, \mu F\)
- B \(RL\) circuit with \(R = 1\, k\,\Omega \) and \(L = 10\, mH\)
- C \(RL\) circuit with \(R = 1\, k\,\Omega \) and \(L = 1\, mH\)
- D \(RC\) circuit with \(R = 1\, k\,\Omega \) and \(C = 10\, \mu F\)
Answer & Solution
Correct Answer
(D) \(RC\) circuit with \(R = 1\, k\,\Omega \) and \(C = 10\, \mu F\)
Step-by-step Solution
Detailed explanation
Given phase difference \(=\frac{\pi}{4}\) and \(\omega=100\) \(rad/s\) \(\Rightarrow\) Reactance \((X)=\) Resistance \((R)\) Now by checking option. Option \((A)\) \(\mathrm{R}=1000 \,\Omega\) and \(\mathrm{X}_{\mathrm{c}}=\frac{1}{10^{-6} \times 100}=10^{4} \,\Omega\) Option…
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