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JEE Mains · Physics · STD 11 - System of particles and rotational motion
  • JEE Mains 2023
  • Medium
  • Numerical

A solid cylinder is released from rest from the top of an inclined plane of inclination \(30^{\circ}\) and length \(60\,cm\). If the cylinder rolls without slipping, its speed upon reaching the bottom of the inclined plane is \(...........ms ^{-1}\). (Given \(g =10\,ms ^{-2}\))

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Answer & Solution

Correct Answer

(B) \(2\)

Step-by-step Solution

Detailed explanation

\(v=\sqrt{\frac{2 g h}{1+\frac{k^2}{R^2}}}\)

Where \(h=60 \sin 30^{\circ}=30\,cm\)

\(k^2=\frac{R^2}{2}\)

\(v=2\,ms ^{-1}\)

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