JEE Mains · Physics · STD 11 - System of particles and rotational motion
- JEE Mains 2023
- Medium
- Numerical
A solid cylinder is released from rest from the top of an inclined plane of inclination \(30^{\circ}\) and length \(60\,cm\). If the cylinder rolls without slipping, its speed upon reaching the bottom of the inclined plane is \(...........ms ^{-1}\). (Given \(g =10\,ms ^{-2}\))

Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(2\)
Step-by-step Solution
Detailed explanation
\(v=\sqrt{\frac{2 g h}{1+\frac{k^2}{R^2}}}\)
Where \(h=60 \sin 30^{\circ}=30\,cm\)
\(k^2=\frac{R^2}{2}\)
\(v=2\,ms ^{-1}\)
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