JEE Mains · Physics · STD 11 - 10.1, thermonetry,thermal expansion and calorimetry
An experiment takes \(10\, minutes\) to raise the temperature of water in a container from \(0\,^oC\) to \(100\,^oC\) and another \(55\, minutes\) to convert it totally into steam by a heater supplying heat at a uniform rate . Neglecting the specific heat of the container and taking specific heat of water to be \(1\, cal / g\,^oC\), the heat of vapourization according to this experiment will come out to be ........ \(cal/g\)
- A \(560\)
- B \(550\)
- C \(540\)
- D \(530\)
Answer & Solution
Correct Answer
(B) \(550\)
Step-by-step Solution
Detailed explanation
\(As\,{p_t} = mC\Delta T\) \(So,\,p \times 10 \times 60 = m\,C\,100\,\,\,...\left( i \right)\) \(and\,p \times 55 \times 60 = mL\,\,\,\,\,\,\,\,\,...\left( {ii} \right)\) Dividing equation \((i)\) by \((ii)\) we get \(\frac{{10}}{{55}} = \frac{{C \times 100}}{L}\)…
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