JEE Mains · Physics · STD 11 - 10.1, thermonetry,thermal expansion and calorimetry
- JEE Mains 2015
- Medium
- Numerical
An experiment takes \(10\, minutes\) to raise the temperature of water in a container from \(0\,^oC\) to \(100\,^oC\) and another \(55\, minutes\) to convert it totally into steam by a heater supplying heat at a uniform rate . Neglecting the specific heat of the container and taking specific heat of water to be \(1\, cal / g\,^oC\), the heat of vapourization according to this experiment will come out to be ........ \(cal/g\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(550\)
Step-by-step Solution
Detailed explanation
\(As\,{p_t} = mC\Delta T\)
\(So,\,p \times 10 \times 60 = m\,C\,100\,\,\,...\left( i \right)\)
\(and\,p \times 55 \times 60 = mL\,\,\,\,\,\,\,\,\,...\left( {ii} \right)\)
Dividing equation \((i)\) by \((ii)\) we get
\(\frac{{10}}{{55}} = \frac{{C \times 100}}{L}\)
\(\therefore L = 550\,cal/g.\)
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