JEE Mains · Physics · STD 11 - 7. gravitation
A body is moving in a low circular orbit about a planet of mass \(M\) and radius \(R\). The radius of the orbit can be taken to be \(R\) it self. Then the ratio of the speed of this body in the orbit to the escape velocity from the planet is
- A \(1\)
- B \(2\)
- C \(\frac{1}{\sqrt{2}}\)
- D \(\sqrt{2}\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{\sqrt{2}}\)
Step-by-step Solution
Detailed explanation
\(V_{\text {orbit }}=\sqrt{\frac{G M}{R}}\) \(V_{\text {escape }}=\sqrt{\frac{2 G M}{R}}\) \(\frac{V_{\text {orbit }}}{V_{\text {escape }}}=\frac{1}{\sqrt{2}}\)
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