JEE Mains · Physics · STD 11 - 7. gravitation
Two stars of masses \(m\) and \(2\, m\) at a distance \(d\) rotate about their common centre of mass in free space. The period of revolution is
- A \(\frac{1}{2 \pi} \sqrt{\frac{ d ^{3}}{3 Gm }}\)
- B \(2 \pi \sqrt{\frac{ d ^{3}}{3 Gm }}\)
- C \(\frac{1}{2 \pi} \sqrt{\frac{3 Gm }{ d ^{3}}}\)
- D \(2 \pi \sqrt{\frac{3 Gm }{ d ^{3}}}\)
Answer & Solution
Correct Answer
(B) \(2 \pi \sqrt{\frac{ d ^{3}}{3 Gm }}\)
Step-by-step Solution
Detailed explanation
\(F=\frac{G(2 m) m }{ d ^{2}}=(2 m ) \omega^{2}( d / 3)\) \(\frac{ Gm }{ d ^{2}}=\omega^{2} \frac{ d }{3}\) \(\Rightarrow \omega^{2}=\frac{3 Gm }{ d ^{3}}\) \(\Rightarrow \omega=\sqrt{\frac{3 Gm }{ d ^{3}}}\)…
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