ExamBro
ExamBro
JEE Mains · Physics · STD 12 - Current electricity
  • JEE Mains 2022
  • Medium
  • MCQ

Two cells of same emf but different internal resistances \(I_{1}\) and \(I_{2}\) are connected in series with a resistance \(R\). The value of resistance \(R\), for which the potential difference across second cell is zero, is

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(A) \(r _{2}- r _{1}\)

Step-by-step Solution

Detailed explanation

\(I=\frac{2 E }{R+I_{1}+I_{2}} \ldots \text{(i)}\)

But \(V _{ A }- V _{ B }= E - I _{2}=0\)

\(\Rightarrow I =\frac{ E }{ I _{2}} \ldots \text{(ii)}\)

Comparing values of \(I\) from \((i)\) and \((ii)\)

\(\frac{E}{r_{2}}=\frac{2 E}{R+r_{1}+r_{2}}\)

\(\Rightarrow R=r_{2}-r_{1}\)

Same subject
Explore more questions on app