JEE Mains · Physics · STD 12 - 14. Semicondutor electronics
A potential barrier of \(0.4 \,V\) exists across a p-n junction. An electron enters the junction from the \(n\)-side with a speed of \(6.0 \times 10^{5} \,ms ^{-1}\). The speed with which electron enters the \(p\) side will be \(\frac{x}{3} \times 10^{5} \,ms ^{-1}\) the value of \(x\) is .............. (Given mass of electron \(=9 \times 10^{-31} \,kg\), charge on electron \(=1.6 \times 10^{-19} \,C\).)
- A \(11\)
- B \(13\)
- C \(14\)
- D \(20\)
Answer & Solution
Correct Answer
(C) \(14\)
Step-by-step Solution
Detailed explanation
Work done by Electric field \(=K_{ r }- K _{ I }\) \(\frac{1}{2} mv ^{2}-\frac{1}{2} mu ^{2}=-1.6-10^{-19} \times 0.4\) \(\frac{1}{2} 9 \times 10^{-31}\left( v ^{2}- u ^{2}\right)=-0.64 \times 10^{-19}\) \(u ^{2}- v ^{2}=\frac{2 \times 0.64 \times 10^{12}}{9}\)…
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