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JEE Mains · Physics · STD 11 - Motion in plane
  • JEE Mains 2025
  • Hard
  • Numerical


A string of length \(L\) is fixed at one end and carries a mass of \(M\) at the other end. The mass makes \(\left(\frac{3}{\pi}\right)\) rotations per second about the vertical axis passing through end of the string as shown. The tension in the string is \(\ldots\ldots\) ML.

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Answer & Solution

Correct Answer

(B) 36

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & \omega=\frac{3}{\pi} \times 2 \pi=6 \mathrm{rad} / \mathrm{s} \\ & R=L \sin \theta\end{aligned}\)

and \(T=M \sqrt{g^2+\omega^4 R^2}\)
Also, \(T \sin \theta=M \omega^2 \cdot L \sin \theta\)
\(\begin{aligned}
& \Rightarrow \quad T=M(36) \mathrm{L} \\
& \Rightarrow \quad T=36 \mathrm{ML}
\end{aligned}\)
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