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JEE Mains · Physics · STD 11 - Units,dimensions and measurement
  • JEE Mains 2021
  • Hard
  • Numerical

The diameter of a spherical bob is measured using a vernier callipers. \(9\) divisions of the main scale, in the vernier callipers, are equal to \(10\) divisions of vernier scale. One main scale division is \(1\, {mm}\). The main scale reading is \(10\, {mm}\) and \(8^{\text {th }}\) division of vernier scale was found to coincide exactly with one of the main scale division. If the given vernier callipers has positive zero error of \(0.04\, {cm}\), then the radius of the bob is \(...... \,\times 10^{-2} \,{cm}\)

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Answer & Solution

Correct Answer

(D) \(52\)

Step-by-step Solution

Detailed explanation

\(9 \,{MSD}=10 \,{VSD}\)

\(9 \times 1\, {mm}=10\, {VSD}\)

\(\therefore 1 \,{VSD}=0.9\, {mm}\)

\({LC}=1\, {MSD}-1\, {VSD}=0.1 \,{mm}\)

Reading \(={MSR}+{VSR} \times {LC}\)

\(10+8 \times 0.1=10.8\, {mm}\)

Actual reading \(=10.8-0.4=10.4\, {mm}\)

radius \(=\frac{{d}}{2}=\frac{10.4}{2}=5.2 \,{mm}\)

\(=52 \times 10^{-2}\, {cm}\)

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