JEE Mains · Physics · STD 11 - 9.1 fluid mechanics
Mercury is filled in a tube of radius \(2 \mathrm{~cm}\) up to a height of \(30 \mathrm{~cm}\). The force exerted by mercury on the bottom of the tube is _______ \(\mathrm{N}\). (Given, atmospheric pressure \(=10^5 \mathrm{Nm}^{-2}\), density of mercury \(=1.36 \times 10^4 \mathrm{~kg} \mathrm{~m}^3, \mathrm{~g}=10 \mathrm{~ms}^2\), \(\left.\pi=\frac{22}{7}\right)\)
- A \(176\)
- B \(177\)
- C \(178\)
- D \(179\)
Answer & Solution
Correct Answer
(B) \(177\)
Step-by-step Solution
Detailed explanation
\(\mathrm{F}=\mathrm{P}_0 \mathrm{~A}+\rho_{\mathrm{m}} \mathrm{ghA}\) \(=10^5 \times \frac{22}{7} \times\left(2 \times 10^{-2}\right)^2\) \(+1.36 \times 10^4 \times 10 \times\left(30 \times 10^{-2}\right)\left(\frac{22}{7} \times\left(2 \times 10^{-2}\right)^2\right)\)…
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