JEE Mains · Physics · STD 11 - 7. gravitation
Four identical particles of mass \(m\) are kept at the four corners of a square. If the gravitational force exerted on one of the masses by the other masses is \(\left(\frac{2 \sqrt{2}+1}{32}\right) \frac{\mathrm{Gm}^2}{\mathrm{~L}^2}\), the length of the sides of the square is _______.
- A \(\frac{L}{2}\)
- B \(4 \mathrm{~L}\)
- C \(3 \mathrm{~L}\)
- D \(2 \mathrm{~L}\)
Answer & Solution
Correct Answer
(B) \(4 \mathrm{~L}\)
Step-by-step Solution
Detailed explanation
\(F_{\text {net }}=\sqrt{2} F+F^{\prime}\) \(F=\frac{G m^2}{a^2} \text { and } F^{\prime}=\frac{G m^2}{(\sqrt{2} a)^2}\) \(F_{\text {net }}=\sqrt{2} \frac{G m^2}{a^2}+\frac{G m^2}{2 a^2}\)…
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