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JEE Mains · Physics · STD 12 - Wave optics
  • JEE Mains 2022
  • Medium
  • Numerical

Sodium light of wavelengths \(650\, nm\) and \(655\, nm\) is used to study diffraction at a single slit of aperture \(0.5\, mm\). The distance between the slit and the screen is \(2.0 \,m\). The separation between the positions of the first maxima of diffraction pattern obtained in the two cases is \(\times 10^{-5} \,m\)

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Answer & Solution

Correct Answer

(C) \(3\)

Step-by-step Solution

Detailed explanation

\(\operatorname{asin} \theta=\frac{3 \lambda}{2}\)

\(\frac{ y }{ L }=\theta=\frac{3 \lambda}{2 a } \quad L =2 m\)

\(y _{1}=\frac{3 \lambda_{1} L }{2 a } \quad \lambda_{2}=655\, nm\)

\(y _{2}=\frac{3 \lambda_{2} L }{2 a } \quad \lambda_{1}=650\, nm\)

\(a=0.5 \,nm\)

\(\Delta y = y _{2}- y _{1}=\frac{3\left(\lambda_{2}-\lambda_{1}\right)}{2 a } L\)

\(=\frac{3(655-650)}{2 \times 0.5 \times 10^{-3}} \times 2 \times 10^{-9}\)

\(=\frac{3 \times 5 \times 2}{1 \times 10^{-3}} \times 10^{-9}\)

\(=3 \times 10^{-5}\)

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