JEE Mains · Physics · STD 12 - Wave optics
- JEE Mains 2022
- Medium
- Numerical
Sodium light of wavelengths \(650\, nm\) and \(655\, nm\) is used to study diffraction at a single slit of aperture \(0.5\, mm\). The distance between the slit and the screen is \(2.0 \,m\). The separation between the positions of the first maxima of diffraction pattern obtained in the two cases is \(\times 10^{-5} \,m\)
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Answer & Solution
Correct Answer
(C) \(3\)
Step-by-step Solution
Detailed explanation
\(\operatorname{asin} \theta=\frac{3 \lambda}{2}\)
\(\frac{ y }{ L }=\theta=\frac{3 \lambda}{2 a } \quad L =2 m\)
\(y _{1}=\frac{3 \lambda_{1} L }{2 a } \quad \lambda_{2}=655\, nm\)
\(y _{2}=\frac{3 \lambda_{2} L }{2 a } \quad \lambda_{1}=650\, nm\)
\(a=0.5 \,nm\)
\(\Delta y = y _{2}- y _{1}=\frac{3\left(\lambda_{2}-\lambda_{1}\right)}{2 a } L\)
\(=\frac{3(655-650)}{2 \times 0.5 \times 10^{-3}} \times 2 \times 10^{-9}\)
\(=\frac{3 \times 5 \times 2}{1 \times 10^{-3}} \times 10^{-9}\)
\(=3 \times 10^{-5}\)
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