An \(HCl\) molecule has rotational, translational and vibrational motions. If the \(rms\) velocity of \(HCl\) molecules in its gaseous phase is \(\bar v ,\,m\) is its mass and \(k_B\) is Boltzmann constant, then its temperature will be

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Answer & Solution

Correct Answer

(A) \(\frac{{m{\bar v ^{ 2}}}}{{3{k_B}}}\)

Step-by-step Solution

Detailed explanation

According to equipartion energy theorem

\(\frac{1}{2} m\left(v_{m s}^{2}\right)=3 \times \frac{1}{2} k_{b} T\)

\(T=\frac{m \bar{V}_{r m s}^{-2}}{3 k}\)

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Match List - I with List - II.
List - I List - II
A. Boltzmann constant I. \([M^{-1}L^3T^{-2}]\)
B. Stefan's constant II. \([ML^2T^{-1}]\)
C. Planck's constant III. \([ML^2T^{-2}K^{-1}]\)
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A. Boltzmann constant	I. \([M^{-1}L^3T^{-2}]\)
B. Stefan's constant	II. \([ML^2T^{-1}]\)
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