JEE Mains · Physics · STD 11 - Waves and sound
- JEE Mains 2017
- Hard
- Numerical
A standing wave is formed by the superposition of two waves travelling in opposite directions. The transverse displacement is given by \(y\left( {x,t} \right) = 0.5\sin\, \left( {\frac{{5\pi }}{4}x} \right)\,\cos\, \left( {200\,\pi t} \right)\). What is the speed of the travelling wave moving in the positive \(x\) direction .... \(m/s\) ? (\(x\) and \(t\) are in meter and second, respectively.)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(160\)
Step-by-step Solution
Detailed explanation
Given, \(y(x, t)=0.5 \sin \left(\frac{5 \pi}{4}x\right) \cos (200 \pi t)\)
comparing with equation \(-y(x, t)=2 a sin\mathrm{kx} \cos \omega \mathrm{t}\)
\(\omega=200 \pi, k=\frac{5 \pi}{4}\)
speed of travelling wave
\(v=\frac{\omega}{k}=\frac{200 \pi}{5 \pi / 4}=160 \mathrm{m} / \mathrm{s}\)
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