JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
For combustion of one mole of magnesium in an open container at \(300 \,K\) and \(1\, bar\) pressure, \(\Delta_{ C } H ^{\ominus}\) \(=-601.70 \,kJ\, mol ^{-1}\), the magnitude of change in internal energy for the reaction is \(....\,kJ\). (Nearest integer) (Given : \(R =8.3 \,J \,K ^{-1}\, mol ^{-1}\) )
- A \(1200\)
- B \(600\)
- C \(120\)
- D \(900\)
Answer & Solution
Correct Answer
(B) \(600\)
Step-by-step Solution
Detailed explanation
\(Mg ( s )+\frac{1}{2} O _{2}( g ) \rightarrow MgO ( s )\) \(\Delta H =\Delta U +\Delta n _{ g } RT\) \(-601.70 \times 10^{3}=\Delta U -\frac{1}{2} \times 8.3 \times 300\) \(-601.70\, kJ =\Delta U -1.245\, kJ\) \(\Delta U =-600.455\, kJ\)
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