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JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry

For combustion of one mole of magnesium in an open container at \(300 \,K\) and \(1\, bar\) pressure, \(\Delta_{ C } H ^{\ominus}\) \(=-601.70 \,kJ\, mol ^{-1}\), the magnitude of change in internal energy for the reaction is \(....\,kJ\). (Nearest integer) (Given : \(R =8.3 \,J \,K ^{-1}\, mol ^{-1}\) )

  1. A \(1200\)
  2. B \(600\)
  3. C \(120\)
  4. D \(900\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(600\)

Step-by-step Solution

Detailed explanation

\(Mg ( s )+\frac{1}{2} O _{2}( g ) \rightarrow MgO ( s )\) \(\Delta H =\Delta U +\Delta n _{ g } RT\) \(-601.70 \times 10^{3}=\Delta U -\frac{1}{2} \times 8.3 \times 300\) \(-601.70\, kJ =\Delta U -1.245\, kJ\) \(\Delta U =-600.455\, kJ\)