JEE Mains · Chemistry · STD 11 - 9. Hydricarbon

Compound (X) [styrene] is subjected to the sequence of reactions as shown above: (i) \(Br_2/CHCl_3\) (ii) \(NaNH_2\) excess (iii) \(CH_3I\) (iv) \(H_2\), \(Na/NH_3\) \((l)\), giving Major Product (Y). Molar mass of the major product (Y) formed is ______ g mol\(^{-1}\).
(Given molar mass in g mol\(^{-1}\) C:\(12\), H: \(1\), O: \(16\))
- A \(90\)
- B \(118\)
- C \(160\)
- D \(125\)
Answer & Solution
Correct Answer
(B) \(118\)
Step-by-step Solution
Detailed explanation
Addition of \(Br_2\) to styrene (X) yields 1,2-dibromoethylbenzene. \(C_6H_5-CH=CH_2 \xrightarrow{Br_2/CHCl_3} C_6H_5-CH(Br)-CH_2(Br)\) Reaction with excess \(NaNH_2\) causes double dehydrohalogenation followed by deprotonation of the terminal alkyne, forming sodium…
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