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JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
\(12\, g\) of a nonvolatile solute dissolved in \(108\, g\) of water produces the relative lowering of vapour pressure of \(0.1\). The molecular mass of the solute is
- A \(80\)
- B \(60\)
- C \(20\)
- D \(40\)
Answer & Solution
Correct Answer
(C) \(20\)
Step-by-step Solution
Detailed explanation
\(\frac{{{P^o}\, - \,{P_s}}}{{{P^o}}}\, = \,\frac{n}{N}\, = \,\frac{w}{m}\, \times \,\frac{M}{W}\) \(0.1\, = \,\frac{{12}}{m}\, \times \,\frac{{18}}{{108}}\) \(m\, = \,\frac{{12\, \times \,18}}{{0.1\, \times \,108}}\, = \,20\)
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