JEE Mains · Physics · STD 12 - 11. Dual nature of radiation and matter
Proton \((P)\) and electron \((e)\) will have same deBroglie wavelength when the ratio of their momentum is (assume, \(m _{ p }=1849\,m _{ e }\))
- A \(1: 43\)
- B \(43: 1\)
- C \(1: 1849\)
- D \(1: 1\)
Answer & Solution
Correct Answer
(D) \(1: 1\)
Step-by-step Solution
Detailed explanation
De Broglie wavelength is \(\lambda=\frac{h}{ mv }\) \(\lambda_{ p }=\lambda_{ e } \Rightarrow m _{ p } v _{ p }= m _{ e } v _{ e } \Rightarrow p _{ p }= p _{ e }\)
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