JEE Mains · Physics · STD 11 - Work,energy,power and collision
- JEE Mains 2024
- Hard
- MCQ
A bullet of mass \(50 \mathrm{~g}\) is fired with a speed \(100 \mathrm{~m} / \mathrm{s}\) on a plywood and emerges with \(40 \mathrm{~m} / \mathrm{s}\). The percentage loss of kinetic energy is _______.
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(84 \%\)
Step-by-step Solution
Detailed explanation
\(\mathrm{K}_{\mathrm{i}} =\frac{1}{2} \mathrm{~m}(100)^2\)
\(\mathrm{~K}_{\mathrm{f}} =\frac{1}{2} \mathrm{~m}(40)^2\)
\(\% \text { loss }=\frac{\left|\mathrm{K}_{\mathrm{f}}-\mathrm{K}_{\mathrm{i}}\right|}{\mathrm{K}_{\mathrm{i}}} \times 100\)
\(=\frac{\left|\frac{1}{2} \mathrm{~m}(40)^2-\frac{1}{2} \mathrm{~m}(100)^2\right|}{\frac{1}{2} \mathrm{~m}(100)^2} \times 100\)
\(=\frac{|1600-100 \times 100|}{100}=84 \%\)
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