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JEE Mains · Physics · STD 11 - Work,energy,power and collision
  • JEE Mains 2024
  • Hard
  • MCQ

A bullet of mass \(50 \mathrm{~g}\) is fired with a speed \(100 \mathrm{~m} / \mathrm{s}\) on a plywood and emerges with \(40 \mathrm{~m} / \mathrm{s}\). The percentage loss of kinetic energy is _______.

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Answer & Solution

Correct Answer

(D) \(84 \%\)

Step-by-step Solution

Detailed explanation

\(\mathrm{K}_{\mathrm{i}} =\frac{1}{2} \mathrm{~m}(100)^2\)

\(\mathrm{~K}_{\mathrm{f}} =\frac{1}{2} \mathrm{~m}(40)^2\)

\(\% \text { loss }=\frac{\left|\mathrm{K}_{\mathrm{f}}-\mathrm{K}_{\mathrm{i}}\right|}{\mathrm{K}_{\mathrm{i}}} \times 100\)

\(=\frac{\left|\frac{1}{2} \mathrm{~m}(40)^2-\frac{1}{2} \mathrm{~m}(100)^2\right|}{\frac{1}{2} \mathrm{~m}(100)^2} \times 100\)

\(=\frac{|1600-100 \times 100|}{100}=84 \%\)

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