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JEE Mains · Physics · STD 11 - 10.2 transmission of heat

\(25^{\circ} C\) कक्ष ताप पर कोई पिण्ड \(5\) मिनट में \(75^{\circ} C\) से \(65^{\circ} C\) तक ठंडा होता है। इस पिण्ड का अगले \(5\) मिनट के अंत में ताप \(......\,{ }^{\circ} C\) होगा।

  1. A \(57\)
  2. B \(60\)
  3. C \(61\)
  4. D \(570\)
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Answer & Solution

Correct Answer

(A) \(57\)

Step-by-step Solution

Detailed explanation

By newton's law of cooling (with approximation) \(\frac{\Delta {T}}{\Delta {t}}=-{C}\left({T}_{{avg}}-{T}_{{s}}\right)\) \(1^{\text {st }}\, \frac{-10^{\circ} {C}}{5\, {min}}=-{C}\left(70^{\circ} {C}-25^{\circ} {C}\right)\) \({C}=\frac{2}{45}\, {min}^{-1}\)…
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