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JEE Mains · Physics · STD 11 - 10.2 transmission of heat

In \(5\, minutes,\) a body cools from \(75^{\circ} {C}\) to \(65^{\circ} {C}\) at room temperature of \(25^{\circ} {C}\). The temperature of body at the end of next \(5\, minutes\) is \(......\,{ }^{\circ} {C} .\)

  1. A \(57\)
  2. B \(60\)
  3. C \(61\)
  4. D \(570\)
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Answer & Solution

Correct Answer

(A) \(57\)

Step-by-step Solution

Detailed explanation

By newton's law of cooling (with approximation) \(\frac{\Delta {T}}{\Delta {t}}=-{C}\left({T}_{{avg}}-{T}_{{s}}\right)\) \(1^{\text {st }}\, \frac{-10^{\circ} {C}}{5\, {min}}=-{C}\left(70^{\circ} {C}-25^{\circ} {C}\right)\) \({C}=\frac{2}{45}\, {min}^{-1}\)…
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