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JEE Mains · Physics · STD 11 - 2. motion in straight line

પદાર્થે \(t\) સમયમાં કાપેલું અંતર \(s=(2.5) t^2\) છે .\(t=5\,s\) સમયે પદાર્થની તત્કાલિન ઝડપ \(........\,ms^{-1}\) હશે.

  1. A \(12.5\)
  2. B \(62.5\)
  3. C \(5\)
  4. D \(25\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(25\)

Step-by-step Solution

Detailed explanation

Distance \((s)=(2.5) t^2\) Speed \(( v )=\frac{ ds }{ dt }=\frac{ d }{ dt }\left\{(2.5) t ^2\right\}\) \(v =5\,t\) At \(t =5, v =5 \times 5=25\,m / s\)
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