હવામાં \(\lambda_1\) તરંગલંબાઈ અને \(\nu_1\) આવૃત્તિ ધરાવતું એક એકવર્ણી તરંગ બીજા માધ્યમમાં પ્રવેશે છે. જો આંતર પૃષ્ઠ પર આપાતકોણ અને વક્રીભવનકોણ અનુક્રમે \(45^{\circ}\) અને \(30^{\circ}\) છે. તો વક્રીભૂત તરંગની તરંગલંબાઈ \(\lambda_2\) અને આવૃત્તિ પર \(\nu_2\) હોય, તો

A \(\lambda_2=\lambda_1, v_2=\sqrt{2} v_1\)
B \(\lambda_2=\frac{1}{\sqrt{2}} \lambda_1, v_2=v_1\)
C \(\lambda_2=\sqrt{2} \lambda_1, v_2=v_1\)
D \(\lambda_2=\lambda_1, v_2=\frac{1}{\sqrt{2}} v_1\)

Verified Solution

Answer & Solution

Correct Answer

(B) \(\lambda_2=\frac{1}{\sqrt{2}} \lambda_1, v_2=v_1\)

Step-by-step Solution

Detailed explanation

Snell's law \(\mu_1 \sin 45^{\circ}=\mu_2 \sin 30^{\circ}\) \(\frac{\mu_1}{\mu_2}=\frac{1}{\sqrt{2}}\) \(\Rightarrow \frac{\mu_1}{\mu_2}=\frac{\lambda_2}{\lambda_1}=\frac{1}{\sqrt{2}}\) \(\Rightarrow \lambda_2=\frac{\lambda_1}{\sqrt{2}}\) Frequency doesn't change on change in…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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