A monochromatic light wave with wavelength \(\lambda_1\) and frequency \(v_1\) in air enters another medium. If the angle of incidence and angle of refraction at the interface are \(45^{\circ}\) and \(30^{\circ}\) respectively, then the wavelength \(\lambda_2\) and frequency \(v_2\) of the refracted wave are :

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Verified Solution

Answer & Solution

Correct Answer

(B) \(\lambda_2=\frac{1}{\sqrt{2}} \lambda_1, v_2=v_1\)

Detailed explanation

Snell's law \(\mu_1 \sin 45^{\circ}=\mu_2 \sin 30^{\circ}\)

\(\frac{\mu_1}{\mu_2}=\frac{1}{\sqrt{2}}\)

\(\Rightarrow \frac{\mu_1}{\mu_2}=\frac{\lambda_2}{\lambda_1}=\frac{1}{\sqrt{2}}\)

\(\Rightarrow \lambda_2=\frac{\lambda_1}{\sqrt{2}}\)

Frequency doesn't change on change in medium.

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