એક પારિમાણિક ગતિ કરતાં કણે કાપેલું અંતર સમય \(t\) પર \(\mathrm{x}^{2}=\mathrm{at}^{2}+2 \mathrm{bt}+\mathrm{c}\) મુજબ આધાર રાખે છે. જો કણનો પ્રવેગ કાપેલા અંતર \(\mathrm{x}\) પર  \(\mathrm{x}^{-\mathrm{n}}\) મુજબ આધાર રાખે છે, જ્યાં \(n\) પૂર્ણાંક છે, તો \(\mathrm{n}\) નું મૂલ્ય કેટલું હશે?

Differentiating w.r.t. time

\(\frac{d x}{d t}=v=\frac{1}{2 \sqrt{a t^{2}+2 b t+c}} \times(2 a t+2 b)\)

\(\Rightarrow \mathrm{v}=\frac{\mathrm{at}+\mathrm{b}}{\mathrm{x}}\)

\(\Rightarrow \mathrm{vx}=\mathrm{at}+\mathrm{b}\)

Differentiating w.r.t. \(\mathrm{x}\)

\(\Rightarrow \frac{d v}{d x} \times x+v=a \times \frac{d t}{d x}\)

Multiply both side by v

\(\Rightarrow\left(v \frac{d v}{d x}\right) x+v^{2}=a\)

\(\Rightarrow \mathrm{a}^{\prime} \mathrm{x}=\mathrm{a}-\mathrm{v}^{2}\) [Here \(a'\) is acceleration]

\(\Rightarrow \mathrm{a}^{\prime} \mathrm{x}=\mathrm{a}-\left(\frac{\mathrm{at}+\mathrm{b}}{\mathrm{x}}\right)^{2}\)

\(\Rightarrow \mathrm{a}^{\prime} \mathrm{x}=\frac{\mathrm{ax}^{2}-(\mathrm{at}+\mathrm{b})^{2}}{\mathrm{x}^{2}}\)

\(\Rightarrow \mathrm{a}^{\prime} \mathrm{x}=\frac{\mathrm{a}\left(\mathrm{at}^{2}+2 \mathrm{bt}+\mathrm{c}\right)-(\mathrm{at}+\mathrm{b})^{2}}{\mathrm{x}^{2}}\)

\(\Rightarrow \mathrm{a}^{\prime} \mathrm{x}=\frac{\mathrm{ac}-\mathrm{b}^{2}}{\mathrm{x}^{2}}\)

\(\Rightarrow \mathrm{a}^{\prime}=\frac{\mathrm{ac}-\mathrm{b}^{2}}{\mathrm{x}^{3}}\)

\(\therefore a^{\prime} \propto \frac{1}{x^{3}} \quad \therefore n=3\)