JEE Mains · Physics · STD 12 - 14. Semicondutor electronics

આપેલ લોજિક ગેટ પરિપથ માટે, નીચેનામાંથી કયું સાચું સત્ય કોષ્ટક છે?

A
n m z
0 0 1
0 1 0
1 1 0
1 0 0
B
n m z
0 0 0
0 1 1
1 1 0
1 0 1
C
n m z
0 0 1
0 1 0
1 1 1
1 0 0
D
n m z
0 0 1
0 1 1
1 1 0
1 0 0

Verified Solution

Answer & Solution

Correct Answer

(D)

n	m	z
0	0	1
0	1	1
1	1	0
1	0	0

Step-by-step Solution

Detailed explanation

ગેટ 1 : નીચે n અને m ઇનપુટ્સ સાથે OR ગેટ છે. આઉટપુટ \(=n+m\) ગેટ 2 : એક NAND ગેટ, તેના ઇનપુટ્સ સીધા n અને OR ગેટનું આઉટપુટ ( \(n+m\) ) છે. આઉટપુટ \(z =\overline{ n \cdot( n + m )}\) કારણ કે \(n .( n + m )=( n . n )+( n . m )\) \(= n + n \cdot m = n (1+ m )= n\) ∴ આઉટપુટ…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

સૂચિ \(I\) ને સૂચિ \(II\) સાથે જોડો

સૂચિ - \(I\)	સૂચિ - \(II\)
\((A)\) ટૉર્ક	\((I)\) \({\left[\mathrm{M}^1 \mathrm{~L}^1 \mathrm{~T}^{-2} \mathrm{~A}^{-2}\right]}\)
\((B)\) ચુંબકીય ક્ષેત્ર	\((II)\) \(\left[\mathrm{L}^2 \mathrm{~A}^1\right]\)
\((C)\) ચુંબકીય ચાકમાત્રા	\((III)\) \({\left[\mathrm{M}^1 \mathrm{~T}^{-2} \mathrm{~A}^{-1}\right]}\)
\((D)\) મુક્ત અવકાશની પારગમ્યતા	\((IV)\) \(\left[\mathrm{M}^1 \mathrm{~L}^2 \mathrm{~T}^{-2}\right]\)

નીચે આપેલા વિકલ્પોમાંથી સાચો જવાબ પસંદ કરો :

JEE Mains 2024 Hard

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