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JEE Mains · Physics · STD 12 - Semicondutor electronics
  • JEE Mains 2026
  • Medium
  • MCQ

For the given logic gate circuit, which of the following is the correct truth table?
image

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Verified Solution

Answer & Solution

Correct Answer

(D)

nmz
001
011
110
100

Step-by-step Solution

Detailed explanation

Gate 1 : At bottom there is an OR gate with inputs n & m
out put \(=n+m\)
Gate 2 : A NAND gate, its Input are direct n & the output of OR gate ( \(n+m\) )
out put \(z =\overline{ n \cdot( n + m )}\)
since \(n .( n + m )=( n . n )+( n . m )\)
\(= n + n \cdot m = n (1+ m )= n\)
∴ output \(z =\overline{ n \cdot( n + m )}=\overline{ n }\)
nm\(Z =\overline{ n }\)
001
011
110
100
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