ExamBro
ExamBro
enEnglishhiहिन्दीguગુજરાતી
JEE Mains · Physics · STD 11 - 5. work,energy,power and collision

\(100 \mathrm{~kg}\) દળનો એક બ્લોક \(10 \mathrm{~m}\) સમક્ષિતિજ અંતર સરકે છે. જો સપાટીઓ વચ્યેનો ધર્ષણાંક \(0.4 \)હોય તો ધર્ષણ વિરુદ્ધ જૂલ એકમમાં થતું કાર્ય_______છે.

  1. A \(4200\)
  2. B \(3900\)
  3. C \(4000\)
  4. D \(4500\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(4000\)

Step-by-step Solution

Detailed explanation

Given \(\mathrm{m}=100 \mathrm{~kg}\) \( \mathrm{s}=10 \mathrm{~m} \) \( \mu=0.4\) As \(\mathrm{f}=\mu \mathrm{mg}=0.4 \times 100 \times 10=400 \mathrm{~N}\) Now \(W=f . s=400 \times 10=4000 \mathrm{~J}\)
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app