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JEE Mains · Chemistry · STD 12 - 2. Electrochemistry

ગેલ્વેનિક કોષ માટે, \({Zn}({s})+{Cu}^{2+}(0.02 {M}) \rightarrow {Zn}^{2+}(0.04 {M})+{Cu}({s})\) \({E}_{\text {cell }}=...... \,\times 10^{-2} \,{~V}\) { (નજીકના પૂર્ણાંકમાં) } \({\left[ {E}_{{Cu} / {Cu}^{2+}}^{0}=-0.34\, {~V}, {E}_{2 {n} / {Zn}^{2+}}^{0}=+0.76 \,{~V}\right.}\) \(\left.\frac{2.303 {RT}}{{F}}=0.059\, {~V}\right]\)

  1. A \(1090\)
  2. B \(109\)
  3. C \(10.9\)
  4. D \(1.09\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(109\)

Step-by-step Solution

Detailed explanation

Galvanic cell: \({Zn}_{({s})}+{Cu}_{\left({aq.}\right)}^{+2} \rightarrow {{Zn}^{+2}}+{Cu}({s})\) \(\quad\quad\quad\quad0.02\,M\quad0.04\,M\)…
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