JEE Mains · Chemistry · STD 12 - 2. Electrochemistry
For the galvanic cell, \(\mathrm{Zn}(\mathrm{s})+\mathrm{Cu}^{2+}(0.02 \mathrm{M}) \rightarrow \mathrm{Zn}^{2+}(0.04 \mathrm{M})+\mathrm{Cu}(\mathrm{s})\) \(\mathrm{E}_{\text {cell }}=...... \,\times 10^{-2} \,\mathrm{~V} { (Nearest integer) }\) \({\left[\text { Use }: \mathrm{E}_{\mathrm{Cu} / \mathrm{Cu}^{2+}}^{0}=-0.34\, \mathrm{~V}, \mathrm{E}_{2 \mathrm{n} / \mathrm{Zn}^{2+}}^{0}=+0.76 \,\mathrm{~V}\right.}\) \(\left.\frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.059\, \mathrm{~V}\right]\)
- A \(1090\)
- B \(109\)
- C \(10.9\)
- D \(1.09\)
Answer & Solution
Correct Answer
(B) \(109\)
Step-by-step Solution
Detailed explanation
Galvanic cell: \(\mathrm{Zn}_{(\mathrm{s})}+\mathrm{Cu}_{\left(\mathrm{aq.}\right)}^{+2} \rightarrow {\mathrm{Zn}^{+2}}+\mathrm{Cu}(\mathrm{s})\) \(\quad\quad\quad\quad0.02\,M\quad0.04\,M\)…
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