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JEE Mains · Chemistry · STD 12 - 2. Electrochemistry

\({Cu}({s})\left|{Cu}^{2+}({aq})(0.1 {M}) \| {Ag}^{+}({aq})(0.01 {M})\right| {Ag}({s})\) કોષ માટે,કોષનો પોટેન્શિયલ \({E}_{1}=0.3095\, {~V}\) \({Cu}({s})\left|{Cu}^{2+}({aq})(0.01 {M}) \| {Ag}^{+}({aq})(0.001 {M})\right| {Ag}({s})\) કોષ માટે ,કોષનો પોટેન્શિયલ \(=.....\times 10^{-2} {~V}\) [ઉપયોગ : \(\frac{2.303 {RT}}{{F}}=0.059\) ]

  1. A \(4\)
  2. B \(14\)
  3. C \(28\)
  4. D \(36\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(28\)

Step-by-step Solution

Detailed explanation

Cell reaction is: \({Cu}({s})+2 {Ag}^{+}({aq}) \rightarrow {Cu}^{2+}+2 {Ag}({s})\) Now, \({E}_{\text {cell }}-\frac{0.059}{2} \log \frac{\left[{cu}^{+}+\right]}{\left[{Ag}^{+}\right]^{2}}...(1)\)…
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