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JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)

\(300\,K\) એ નીચેની પ્રક્રિયા માટે \(K_p/K_c\) ની કિંમતો અનુક્રમે કેટલી હશે? ( \(300\, K,\) એ \(RT = 24.62\, dm^3\, atm \,mol^{-1}\)) \({N_2}(g) + {O_2}(g) \rightleftharpoons 2NO(g)\) \({N_2}{O_4}(g) \rightleftharpoons  2N{O_2}(g)\) \({N_2}(g) + 3{H_2}(g) \rightleftharpoons  2N{H_3}(g)\)

  1. A \(1, 24.62\, dm^3\, atm\, mol^{-1}\), \(606.0\, dm^6\, atm^2 \,mol\,^{-2}\)
  2. B \(1, 24.62\, dm^3\, atm\, mol^{-1}\), \(1.65 \times 10^{-3}\, dm^{-6}\, atm^{-2} \,mol\,^{2}\)
  3. C \(1,4.1 \times 10^{-2}\, dm^{-3}\, atm^{-1}\, mol\), \(606.0\, dm^6\, atm^2 \,mol\,^{-2}\)
  4. D \(24.62\, dm^3\, atm\, mol^{-1}\), \(606.0\, dm^6\, atm^2\,atm^2 \,mol\,^{-2}\) , \(1.65 \times 10^{-3}\,dm^{-6}\,atm^{-2}\,mol^2\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(1, 24.62\, dm^3\, atm\, mol^{-1}\), \(1.65 \times 10^{-3}\, dm^{-6}\, atm^{-2} \,mol\,^{2}\)

Step-by-step Solution

Detailed explanation

\({K_p} = {K_{c\,}}{\left( {RT} \right)^{\Delta ng}}\)
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