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JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)

\(300 \,K\) पर, निम्न अभिक्रियाओं के लिए \(K _{ p } / K _{ c }\) के मान क्रमशः होंगे : ( \(300 \,K\) पर RT \(=24.62 \,dm ^{3} atm\) \(mol ^{-1}\) ) \(N _{2}( g )+ O _{2}( g )=2 NO ( g )\) \(N _{2} O _{4}( g )=2 NO _{2}( g )\) \(N _{2}( g )+3 H _{2}( g )=2 NH _{3}( g )\)

  1. A \(1, 24.62\, dm^3\, atm\, mol^{-1}\), \(606.0\, dm^6\, atm^2 \,mol\,^{-2}\)
  2. B \(1, 24.62\, dm^3\, atm\, mol^{-1}\), \(1.65 \times 10^{-3}\, dm^{-6}\, atm^{-2}\, mol\,^{2}\)
  3. C \(1,4.1 \times 10^{-2}\, dm^{-3}\, atm^{-1}\, mol\), \(606.0\, dm^6\, atm^2 \,mol\,^{-2}\)
  4. D \(24.62\, dm^3\, atm\, mol^{-1}\), \(606.0\, dm^6\, atm^2\,atm^2\, mol\,^{-2}\) , \(1.65 \times 10^{-3}\,dm^{-6}\,atm^{-2}\,mol^2\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(1, 24.62\, dm^3\, atm\, mol^{-1}\), \(1.65 \times 10^{-3}\, dm^{-6}\, atm^{-2}\, mol\,^{2}\)

Step-by-step Solution

Detailed explanation

\({K_p} = {K_{c\,}}{\left( {RT} \right)^{\Delta ng}}\)
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