JEE Mains · Physics · STD 11 - Motion in straight line
- JEE Mains 2019
- Easy
- Numerical
A particle starts from the origin at time \(t = 0\) and moves along the positive \(x-\) axis. The graph of velocity with respect to time is shown in figure. What is the position of the particle at time \(t = 5\,s\) ?.........\(m\)

Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(9\)
Step-by-step Solution
Detailed explanation
\(\begin{array}{l}
{r_{t = 5}} = area\\
\,\,\,\,\,\,\,\, = \,\left( {\frac{1}{2} \times 2 \times 2 + 2 \times 2 + 3 \times 1} \right)m\\
\,\,\,\,\,\,\,\, = \left( {2 + 4 + 3} \right)\,m\\
\,\,\,\,\,\,\,\, = 9\,m.
\end{array}\)
{r_{t = 5}} = area\\
\,\,\,\,\,\,\,\, = \,\left( {\frac{1}{2} \times 2 \times 2 + 2 \times 2 + 3 \times 1} \right)m\\
\,\,\,\,\,\,\,\, = \left( {2 + 4 + 3} \right)\,m\\
\,\,\,\,\,\,\,\, = 9\,m.
\end{array}\)
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