JEE Mains · Physics · STD 11 - 2. motion in straight line
A particle starts from the origin at time \(t = 0\) and moves along the positive \(x-\) axis. The graph of velocity with respect to time is shown in figure. What is the position of the particle at time \(t = 5\,s\) ?.........\(m\)
- A \(10\)
- B \(6\)
- C \(3\)
- D \(9\)
Answer & Solution
Correct Answer
(D) \(9\)
Step-by-step Solution
Detailed explanation
\(\begin{array}{l} {r_{t = 5}} = area\\ \,\,\,\,\,\,\,\, = \,\left( {\frac{1}{2} \times 2 \times 2 + 2 \times 2 + 3 \times 1} \right)m\\ \,\,\,\,\,\,\,\, = \left( {2 + 4 + 3} \right)\,m\\ \,\,\,\,\,\,\,\, = 9\,m. \end{array}\)
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