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JEE Mains · Physics · STD 11 - 12 . kinetic theory of gases
The value closest to the thermal velocity of a Helium atom at room temperature \((300\,K)\)in \(ms^{-1}\) is \([k_B\, = 1 .4\times10^{-23}\,J/K;\, m_{He}\, = 7\times10^{-27}\,kg]\)
- A \(1.3\times10^4\)
- B \(1.3\times10^5\)
- C \(1.3\times10^2\)
- D \(1.3\times10^3\)
Answer & Solution
Correct Answer
(D) \(1.3\times10^3\)
Step-by-step Solution
Detailed explanation
\(v = \sqrt {3{k_B}T/{m_{He}}} = \sqrt {\frac{{3 \times 1.4 \times {{10}^{ - 23}} \times 300}}{{7 \times {{10}^{ - 27}}}}} = 1.34 \times {10^3}\,m/s\)
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