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JEE Mains · Physics · STD 11 - Kinetic theory of gases
  • JEE Mains 2018
  • Medium
  • MCQ

The value closest to the thermal velocity of a Helium atom at room temperature \((300\,K)\)in \(ms^{-1}\) is \([k_B\, = 1 .4\times10^{-23}\,J/K;\, m_{He}\, = 7\times10^{-27}\,kg]\)

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Correct Answer

(D) \(1.3\times10^3\)

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\(v = \sqrt {3{k_B}T/{m_{He}}}  = \sqrt {\frac{{3 \times 1.4 \times {{10}^{ - 23}} \times 300}}{{7 \times {{10}^{ - 27}}}}}  = 1.34 \times {10^3}\,m/s\)
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