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JEE Mains · Physics · STD 12 - Magnetism and matter
  • JEE Mains 2023
  • Medium
  • Numerical

A bar magnet with a magnetic moment \(5.0\,Am ^2\) is placed in parallel position relative to a magnetic field of \(0.4\,T\). The amount of required work done in turning the magnet form parallel to antiparallel position relative to the field direction is \(.........\,J\)

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Answer & Solution

Correct Answer

(A) \(4\)

Step-by-step Solution

Detailed explanation

\(u =- MB \cos \theta\)

\(W =\Delta u\)

\(W =- MB \cos 180^{\circ}\left(- mB \cos 0^{\circ}\right)\)

\(W =2 MB =2 \times 5 \times 0.4=4\,J\)

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