JEE Mains · Physics · STD 11 - Motion in straight line
- JEE Mains 2019
- Hard
- MCQ
A passenger train of length \(60\, m\) travels at a speed of \(80\, km/hr\). Another freight train of length \(120\, m\) travels at a speed of \(30\, km/hr\). The ratio of times taken by the passenger train to completely cross the freight train when: \((i)\) they are moving in the same direction, and \((ii)\) in the opposite directions is
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(2.2\)
Step-by-step Solution
Detailed explanation
\(\begin{array}{l}
Time\,taken\,if\,both\,moving\,in\,same\,direcation\\
\,\,\,\,\,\,\,\,\,\,\,\,{t_1} = \frac{{{\rm{distance}}}}{{speed}} = \frac{{0.12 + 0.06}}{{80 - 30}} = \frac{{0.18}}{{50}}\\
Time\,taken\,if\,moving\,in\,opposite\,direction\\
\,\,\,\,\,\,\,\,\,\,\,{t_2} = \frac{{{\rm{distance}}}}{{speed}} = \frac{{0.12 + 0.06}}{{80 + 30}} = \frac{{0.18}}{{110}}\\
\frac{{{t_1}}}{{{t_2}}} = \frac{{11}}{5}
\end{array}\)

Time\,taken\,if\,both\,moving\,in\,same\,direcation\\
\,\,\,\,\,\,\,\,\,\,\,\,{t_1} = \frac{{{\rm{distance}}}}{{speed}} = \frac{{0.12 + 0.06}}{{80 - 30}} = \frac{{0.18}}{{50}}\\
Time\,taken\,if\,moving\,in\,opposite\,direction\\
\,\,\,\,\,\,\,\,\,\,\,{t_2} = \frac{{{\rm{distance}}}}{{speed}} = \frac{{0.12 + 0.06}}{{80 + 30}} = \frac{{0.18}}{{110}}\\
\frac{{{t_1}}}{{{t_2}}} = \frac{{11}}{5}
\end{array}\)

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