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JEE Mains · Physics · STD 11 - 9.2 surface tension
A soap bubble of radius \(3\, {cm}\) is formed inside the another soap bubble of radius \(6\, {cm}\). The radius of an equivalent soap bubble which has the same excess pressure as inside the smaller bubble with respect to the atmospheric pressure is .......... \({cm}\)
- A \(5\)
- B \(4\)
- C \(2\)
- D \(3\)
Answer & Solution
Correct Answer
(C) \(2\)
Step-by-step Solution
Detailed explanation
Excess pressure inside the smaller soap bubble \(\Delta {P}=\frac{4 {S}}{{r}_{1}}+\frac{4 {S}}{{r}_{2}}\ldots \text { (i) }\) The excess pressure inside the equivalent soap bubble \(\Delta {P}=\frac{4 {S}}{{R}_{{eq}}} \ldots \text { (ii) }\) From \( (i) \,\& \,(ii)\)…
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